Let x, y be the volumes; m, n be the masses of two metallic cubes P and Q
Let x, y be the volumes; m, n be the masses of two metallic cubes P and Q respectively. Each side of Q is two times that of P and mass of Q is two times that of P. Let u = m/x and v = n/y. Which one of the following is correct?
- u = 4v
- u = 2v
- v = u
- v = 4u
Answer: A
Explanation
Given: Volume of P = x; Volume of Q = y; Mass of P = m; Mass of Q = n
It is given that, Mass of Q = 2 × Mass of P
Or n = 2m
Also, each side of Q is two times that of P.
Let each side of P be a units and that of Q be 2a units.
So, x = a3
And y = (2a)3 = 8a3
According to the question,
u = m/x
or u = m/a3 (1)
And v = n/y
or v = 2m/8a3 = m/4a3 (2)
From (1) and (2), we get:
u/v = 4
or u = 4v
- Exam Year: 2020